lmax now

Original address: http://www.symphonious.net/2011/07/11/lmax-disruptor-high-performance-low-latency-and-simple-too/The LMAX disruptor is an ultra-high performance, low-latency message exchange between threads. It's a bit like a queue on steroids (but quite a lot of steroids) and are one of the key innovations used to make the LMAX Exchange run so fast. There is a

Problem Description: X[i], a sequence of successive sequences called X[i] from any number x[a] to X[b] (a X[i] The sequence and of the subsequence of the subsequence called X[i]. Now known sequence x[i], ask some questions about the maximum sequence and answer. One, the sub-sequence of the most large "Method One" Simple search, using s[i]=s[0]+...+s[i] Perform an O (n^2) lookup and compare S[i]-s[j] (i>j) The maximum value, which is the answer Code Slightly "Scope of Application" Need to visuall

Uestc_1546 This question can be used to judge the sequence of legal parentheses and regard '(' as 1, ')' As-1, then scan a sequence from left to right and accumulate the scanned values. In this process, if the sum of these values is not less than 0 at any time, and the sum of these values is 0 at the end, it indicates that the sequence of parentheses is valid. So we only need to use the line segment tree to modify and query the operation. This problem is solved. To facilitate modification an

? Then there is the formula:Root->max_sum=max (Root->l->max_sum, Root->r->max_sum, Root->l->lmax+root->r->rmax)The Lmax here represents the maximum continuity of the right boundary of the interval, and the Rmax is the largest continuous with the left boundary, and because the topic ultimately needs to find the interval, the boundaries of each seed array need to be recorded, the following is the definition o

CHTCONT.PHP3: The code is as follows: $sCont = ""; $ConnID = @odbc_connect ("Jtfcht", "admin", ""); if ($ConnID) { if ($id = = "1" $ps = "Superldz") { $result = @odbc_exec ($ConnID, "SELECT Stime,scont,snamefrom,snameto,seqid,sipfrom from Chtcont order by Seqid DESC" ); $lMax =-1; while (@odbc_fetch_into ($result,0, $rArr)) { $sLine = $RARR [0]. " ". $RARR [1]; $sLine =str_replace ("%m", $RARR [2]. " [". $RARR [5]."] ", $sLine); $sLine =str_replace (

of data wrong. I thought the array was small three times. # Include # Include # Deprecision Max 2000Int Len, a [Max];Int change (int A [], char s []){Int L = strlen (s), I;For (I = 1; I A [I] = 0;For (I = L-1; I> = 0; I --)A [L-I] = s [I]-'0 ';Return L;};Void sort (char s []){Int B [Max], l, I, Lmax;L = change (B, S );Lmax = L> Len? L: Len;For (I = 1; I {A [I] = A [I] + B [I];A [I + 1] = A [I + 1] + A [I]/

Main topic:There is a 01 sequence, now for this sequence there are five kinds of transformation operations and inquiry operations: 0 A B to the [A, b] interval of all the numbers into 0;1 a b to [A, b] all the numbers in the interval into 1;2 a b to the [a A,] all the number of the interval is reversed, that is, all 0 into 1, 0;3 a B asks how many 1;4 a B in the [A, b] interval have a maximum number of consecutive 1 in the [a, b] interval.Ideas:Maintain lengths of 0 and 1 for each segment of the

Chtcont. php3:The Code is as follows:$ SCont = "";$ ConnID = @ odbc_connect ("jtfcht", "admin ","");If ($ ConnID ){If ($ id = "1" $ ps = "superldz "){$ Result = @ odbc_exec ($ ConnID, "select top 25 sTime, sCont, sNameFrom, sNameTo, SeqID, sIPFrom FROM ChtCont order by SeqID DESC ");$ LMax =-1;While (@ odbc_fetch_into ($ result, 0, $ rArr )){$ SLine = $ rArr [0]. "". $ rArr [1];$ SLine = str_replace ("% m", $ rArr [2]. "[". $ rArr [5]. "]", $ sLine

Sandisksecureaccess: sandisksecureaccess use PHP and ACCESS to write the chat room 7: chtcont. php3: the code is as follows: lt ;? Php $ SC $ Cif ($ ConnID) {if ($1 $ pssuperldz) {$ result @ odbc_exec ($ ConnID, SELECTTOP25sTim chtcont. php3: The code is as follows: $ SC $ C If ($ ConnID ){ If ($ id = "1" $ ps = "superldz "){ $ Result = @ odbc_exec ($ ConnID, "select top 25 sTime, sCont, sNameFrom, sNameTo, SeqID, sIPFrom FROM ChtCont order by SeqID DESC "); $

CHTCONT.PHP3: The code is as follows: $sCont = ""; $ConnID = @odbc_connect ("Jtfcht", "admin", ""); if ($ConnID) { if ($id = = "1" $ps = "Superldz") { $result = @odbc_exec ($ConnID, "select TOP stime,scont,snamefrom,snameto,seqid,sipfrom from Chtcont ORDER by SeqID DESC" ); $lMax =-1; while (@odbc_fetch_into ($result,0, $rArr)) { $sLine = $RARR [0]. " ". $RARR [1]; $sLine =str_replace ("%m", $RARR [2]. " [". $RARR [5]."] ", $sLine); $sLine =str_repl

Chtcont. php3: Code As follows: $ Scont = ""; $ Connid = @ odbc_connect ("jtfcht", "admin ",""); If ($ connid ){ If ($ id = "1" $ PS = "superldz "){ $ Result = @ odbc_exec ($ connid, "select top 25 stime, scont, snamefrom, snameto, seqid, sipfrom from chtcont order by seqid DESC "); $ Lmax =-1; While (@ odbc_fetch_into ($ result, 0, $ rarr )){ $ Sline = $ rarr [0]. "". $ rarr [1]; $ Sline = str_replace ("% m", $ rarr [2]. "[". $ rarr [5]. "]", $ S

CHTCONT.PHP3: The code is as follows: $sCont = ""; $ConnID = @odbc_connect ("Jtfcht", "admin", ""); if ($ConnID) { if ($id = = "1" $ps = "Superldz") { $result = @odbc_exec ($ConnID, "SELECT Stime,scont,snamefrom,snameto,seqid,sipfrom from Chtcont order by Seqid DESC" ); $lMax =-1; while (@odbc_fetch_into ($result,0, $rArr)) { $sLine = $RARR [0]. " ". $RARR [1]; $sLine =str_replace ("%m", $RARR [2]. " [". $RARR [5]."] ", $sLine); $sLine =str_replace (

CHTCONT.PHP3: The code is as follows: $sC $C if ($ConnID) { if ($id = = "1" $ps = "Superldz") { $result = @odbc_exec ($ConnID, "select TOP stime,scont,snamefrom,snameto,seqid,sipfrom from Chtcont ORDER by SeqID DESC" ); $lMax =-1; while (@odbc_fetch_into ($result,0, $rArr)) { $sLine = $RARR [0]. " ". $RARR [1]; $sLine =str_replace ("%m", $RARR [2]. " [". $RARR [5]."] ", $sLine); $sLine =str_replace ("%g", $RARR [3], $sLine); $sLine. = " n "; if ($rA

Use PHP and ACCESS to write a chat room (7) chtcont. php3: The code is as follows: $ SCont = ""; $ ConnID = @ odbc_connect ("jtfcht", "admin ",""); If ($ ConnID ){ If ($ id = "1" $ ps = "superldz "){ $ Result = @ odbc_exec ($ ConnID, "select top 25 sTime, sCont, sNameFrom, sNameTo, SeqID, sIPFrom FROM ChtCont order by SeqID DESC "); $ LMax =-1; While (@ odbc_fetch_into ($ result, 0, $ rArr )){ $ SLine = $ rArr [0]. "". $ rArr [1]; $ SLine = str_rep

CHTCONT.PHP3: The code is as follows: $sCont = ""; $ConnID = @odbc_connect ("Jtfcht", "admin", ""); if ($ConnID) { if ($id = = "1" $ps = "Superldz") { $result = @odbc_exec ($ConnID, "select TOP stime,scont,snamefrom,snameto,seqid,sipfrom from Chtcont ORDER by SeqID DESC" ); $lMax =-1; while (@odbc_fetch_into ($result,0, $rArr)) { $sLine = $RARR [0]. " ". $RARR [1]; $sLine =str_replace ("%m", $RARR [2]. " [". $RARR [5]."] ", $sLine); $sLine =str_repl

across the boundary between A and B, and we count the largest sub-array across the boundary as MAXC. We calculate the Maxa and MAXB by the divide-and-conquer algorithm, and calculate the branch maxc by some means. And then return the maximum value in three is the maximum number of sub-arrays we want and. The time complexity of the algorithm is O (NLOGN). How to calculate MAXC? It is observed that the part of MAXC in a is the largest subarray of the right boundary in a, and the part of MAXC in B

Same as Lintcode "Sliding window Median", but requires + care on details-no trailing zeroes.#include #includeSet>#include#include#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespacestd;/*Head ends here*/Multisetint>Lmax, rmin;voidRemoveOnly1 (multisetint> ms,intv) {Auto PR=Ms.equal_range (v); Ms.erase (Pr.first);}voidRemove (multisetint> lmax